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Solving differential equations : Differential equation, such as dy / dx = x / y, does not comply with a number and function, in this particular case is such that its graph at any point, for example, at coordinates (2,3) has a tangent with slope equal to relative coordinates (in our example 2 / 3). This is easily seeing, if we construct a large number of points and from each delay a short period with a corresponding slope. How to solve differential equations? -The solution would be a function whose graph regards each point of the corresponding segment. If the points and segments enough, we can roughly outline the shape of the curves-solutions (three of these curves are shown in Fig. 1). There is exactly one curve of the solution passing through each point with y № 0. Each individual solution is called a particular solution of differential equations, if we can find a formula that contains all the partial solutions (except, perhaps, a few individuals), then we say that the general solution. Particular solution is a single function, whereas in common - their whole family. How to solve differential equations - Solve a differential equation - it means to find either its private or a general solution. In our example, the general solution is y2 – x2= c, where c - any number, a particular solution passing through the point (1,1) has the form y = x and is obtained at c = 0; particular solution passing through the point (2,1) has the form y2 – x2= 3. Requiring that the curve is a solution took place, for example, through the point (2, 1), called the initial condition (as sets the starting point on the curve solving). y2 – x2 =4; y2 – x2=0; y2 – x2=-4 We can show that in the example (1) general solution is x = ce–kt, where c - constant, which can be determined, for example, specifying the amount of the substance at t = 0. The equation of Example (2) - a special case of the example (1), corresponding to k = 1 / 100. The initial condition is x = 10 at t = 0 gives the particular solution x = 10e–t/100. The equation of Example (4) has the general solution T = 70 + ce–kt and a particular solution 70 + 130–kt; to determine the value of k, more data needed.
- Equation with multiple variables. |
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